501. Find Mode in Binary Search Tree
Description
Solution
Imagine how we find mode
in an array [1 2 2 4 5 6 6 7], we just scan over then use some variables recording the most frequent number. In this BST, we can use inorder-traversal to get this sorted array.
Code
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 class Solution {public : int maxfreq, prev, curfreq; vector<int > res; vector<int > findMode (TreeNode* root) { dfs (root); return res; } void dfs (TreeNode* root) { if (root == nullptr ) return ; dfs (root->left); if (maxfreq == 0 ){ prev = root->val; curfreq += 1 ; }else { if (prev == root->val){ curfreq+=1 ; }else { curfreq = 1 ; prev = root->val; } } if (curfreq > maxfreq){ while (res.size ()>0 ) res.pop_back (); res.push_back (root->val); maxfreq = curfreq; }else if (curfreq == maxfreq){ res.push_back (root->val); } dfs (root->right); } };